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C U Ø 3 (A ∩ B) U (A ∩ C) 4 B ∩ B (A ∩ B) U (A ∩ C) ({a,b,c,d,e} ∩ {a,f,g,h}) U ({a,b,c,d,e} ∩ {a,c,h,i}) First we do ({a,b,c,d,e} ∩ {a,f,g,h}) Intersection means to take ONLY the elements in common, and and there is only one element in common and that is a So we now have {a} U ({a,b,c,d,e} ∩ {a,c,h,i}) Next, we doç ¯\Ø Í Â C\µ\ó\Ø ~ µ Î Ñ ¢ à \Ø \Õ Ì\Á\ £ \Ã\õ\Ã\ã\Ð\Ø ò X\Õ\´\®\Ð ø Ó µ ¾ ­ ©\µ\ó µ ¾ ©\è\Ñ\Ø ø\Ð\Ø Ñ C\Õ H á\Ã\õ\É\ë\ ~ µ Î Ñ ¢ à \Õ ¬\õ Î ª à H á ¸\Ø ³ Ö\Õ\Î\®\Ð M À\ü £ \Á\è\Ã\ = R 2 ò X a 9 ç ¯ ^ = R 2 Cc J?c) å Xc ª c ãc 4 ;@ A D B w F J I G C H K x y z {} ~}? 1 ŠØ' ƒAƒCƒhƒ‹ "¯Œ^ ƒ{ƒu

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